Operation on Complex numbers using Operator Overloading in C++ | Overloading Insertion and Extraction Operators in C++

Problem Statement: Implement a class Complex which represents the Complex Number data type. Implement the following

    1. Constructor (including a default constructor which creates the complex number 0+0i).

    2. Overload operator+ to add two complex numbers.

    3. Overload operator* to multiply two Complex numbers.

    4. Overload operators << and >> to print and read Complex Numbers.

Note:- Scroll horizontally to see the full line of code.

#include <iostream>

using namespace std;

class complex

{

private:

    float real, img;

public:

    complex()

    {

        real=0;

        img=0;

    }

   

    friend ostream &operator<<( ostream &output,complex &D ) {

         output << D.real << "+" << D.img<< "i \n";

         return output;            

      }

    friend istream &operator>>( istream  &input, complex &D ) {

      cout<<"Enter the real part of complex no.:";

      input>>D.real;

      cout<<"Enter the imaginary part of complex no.:";

      input>>D.img;

      return input;            

    }

    complex operator +(complex  &num2){

        complex a;

        a.real=real+num2.real;

        a.img=img+num2.img;

        return a;

    }

    complex operator -(complex  &num2){

        complex a;

        a.real=real-num2.real;

        a.img=img-num2.img;

        return a;

    }

    complex operator *(complex &num2){

        complex a;

        a.real=(real*num2.real)-(img*num2.img);

        a.img=(real*num2.img)+(img*num2.real);

        return a;

    }

};

 int main()

{

    complex a,b,addition,difference,multiplication;

    cin>>a;

    cin>>b;

    char flag;

    do{

        cout<<"<------Menu------>"<<endl;

        cout<<"1.Addition"<<endl;

        cout<<"2.Substraction"<<endl;

        cout<<"3.Multiplication"<<endl;

        int n;

        cin>>n;

        switch (n)

        {

        case 1:

            addition=a+b;

            cout<<"The addition of two complex no. is";

            cout<<addition;

            break;

        case 2:

            difference=a-b;

            cout<<"The Substraction of two complex no. is";

            cout<<difference;

            break;

        case 3:

            multiplication=a*b;

            cout<<"The Multiplication of two complex no. is";

            cout<<multiplication;

            break;

       

        default:

            cout<<"INVALID CHOICE!";

            break;

        }

        cout<<"\n Do you want to continue? (y/n)";

        cin>>flag;

    }

    while(flag=='y');

    cout<<"Thank You!";

   

    return 0;

}